Tanushree - Maths teacher - Alipurduar
1st lesson free
Tanushree - Maths teacher - Alipurduar

Tanushree's profile and their contact details have been verified by our experts

Tanushree

  • Rate $10
  • Response 1h
Tanushree - Maths teacher - Alipurduar

$10/h

1st lesson free

Contact

1st lesson free

1st lesson free

  • Maths
  • Algebra
  • Trigonometry
  • Arithmetic

Hello, I am Tanushree Das. I am 12th pass. I had taken PCMB in class 11. I got 90.8% in 12th boards and 94% in 10th boards.

  • Maths
  • Algebra
  • Trigonometry
  • Arithmetic

Lesson location

About Tanushree

Hello students, I am here to teach you math. I have scored 98 in 12th boards and 99 in 10th boards. Believe me, math is not that hard. Math is all about practicing and using a little knowledge. I'm here to give you that knowledge, through which you can gain the confidence to solve new problems in a few minutes.

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About the lesson

  • All Levels
  • English

All languages in which the lesson is available :

English

I will teach you easy tricks of math. Math will be no more a boring subject for you all. Just like if, 🟦 Trigonometry Problem: Height of a Building Problem: A person is standing 30 meters away from the base of a building. The angle of elevation from the person’s eyes to the top of the building is 45°. Find the height of the building. (Assume the person’s eye level is at ground level for simplicity.) --- Solution: Use of Tangent Function From the right-angled triangle formed: Let the height of the building = h Distance from the building = 30 meters Angle of elevation = 45° \tan(45°) = \frac{\text{opposite}}{\text{adjacent}} = \frac{h}{30} But we know: \tan(45°) = 1 So, 1 = \frac{h}{30} \Rightarrow h = 30 --- Final Answer: The building is 30 meters

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Rates

Rate

  • $10

Pack rates

  • 5h: $50
  • 10h: $100

online

  • $10/h

free lessons

This first lesson offered with Tanushree will allow you to get to know each other and clearly specify your needs for your next lessons.

  • 1hr

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